Identifying and Correcting Errors

alphabet = "abcdefghijklmnopqrstuvwxyz"

alphabetList = []

for i in alphabet:
    alphabetList.append(i)

print(alphabetList)

print("what letter do you want to check?")

letter = input("Enter letter: ")
if letter == ("a"):
    print("1")
if letter == ("b"):
    print("2")
if letter == ("c"):
    print("3")
if letter == ("d"):
    print("4")
if letter == ("e"):
    print("5")
if letter == ("f"):
    print("6")
if letter == ("g"):
    print("7")
if letter == ("h"):
    print("8")
if letter == ("i"):
    print("9")
if letter == ("j"):
    print("10")
if letter == ("k"):
    print("11")
if letter == ("l"):
    print("12")
if letter == ("m"):
    print("13")
if letter == ("n"):
    print("14")
if letter == ("o"):
    print("15")
if letter == ("p"):
    print("16")
if letter == ("q"):
    print("17")
if letter == ("r"):
    print("18")
if letter == ("s"):
    print("19")
if letter == ("t"):
    print("20")
if letter == ("u"):
    print("21")
if letter == ("v"):
    print("22")
if letter == ("w"):
    print("23")
if letter == ("x"):
    print("24")
if letter == ("y"):
    print("25")
if letter == ("z"):
    print("26")

['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
what letter do you want to check?
1

letter = input("What letter would you like to check?")

i = 0

while i < 26:
    if alphabetList[i] == letter:
        print("The letter " + letter + " is the " + str(i+1) + " letter in the alphabet")
    i += 1

The letter a is the 1 letter in the alphabet

change str(i) to str(i+1) because a =0

letter = input("What letter would you like to check?")
count = 0
for i in alphabetList:
    if i == letter:
        print("The letter " + letter + " is the " + str(count+1) + " letter in the alphabet")
    count += 1

The letter c is the 3 letter in the alphabet

remove count out of for loop

odds = []
i = 1

while i <= 10:
    odds.append(i)
    i += 2

print(odds)    

[1, 3, 5, 7, 9]

changed to i=1 because 1+2, +2, +2, etc will be odd

odds = []
i = 1

while i <= 10:
    odds.append(i)
    i += 2

print(odds)

[1, 3, 5, 7, 9]

changed i=0 to i=1 for same reason as above

numbers = [0,1,2,3,4,5,6,7,8,9,10]
odds = []

for i in numbers:
    if (numbers[i] % 2 != 0):
        odds.append(numbers[i])

print(odds)

[1, 3, 5, 7, 9]

changed evens to odds, replaced == with !=( equal with cannot equal)

numbers = []
newNumbers = []
i = 0

while i <= 100:
    if i == 0:
        pass
    
    numbers.append(i)
    i += 1

for i in numbers:
    if numbers[i] == 0:
        pass
    elif numbers[i] % 5 == 0:
        newNumbers.append(numbers[i])
    elif numbers[i] % 2 == 0:
        newNumbers.append(numbers[i])

print(newNumbers) 

[2, 4, 5, 6, 8, 10, 12, 14, 15, 16, 18, 20, 22, 24, 25, 26, 28, 30, 32, 34, 35, 36, 38, 40, 42, 44, 45, 46, 48, 50, 52, 54, 55, 56, 58, 60, 62, 64, 65, 66, 68, 70, 72, 74, 75, 76, 78, 80, 82, 84, 85, 86, 88, 90, 92, 94, 95, 96, 98, 100]

added pass if i ==0, replaced if with elif (else), for when number isn't 0

menu =  {"burger": 3.99,
         "fries": 1.99,
         "drink": 0.99}
total = 0

#shows the user the menu and prompts them to select an item
print("Menu")
for k,v in menu.items():
    print(k + "  $" + str(v)) #why does v have "str" in front of it?

#ideally the code should prompt the user multiple times
item = input("Please select an item from the menu")
second = input("do you want another item")
#code should add the price of the menu items selected by the user 
print (menu[item] )
print (check[second])
if second = yes
    print (menu[item])
if input = no

  Input In [6]
    if second = yes
              ^
SyntaxError: invalid syntax